Exam 04 Solutions

# Exam 04 Solutions - midterm 04 GADHIA TEJAS Due May 2 2007...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: midterm 04 GADHIA, TEJAS Due: May 2 2007, 11:00 pm 1 Version number encoded for clicker entry: V1:1, V2:1, V3:4, V4:4, V5:5. Question 1 part 1 of 1 10 points A harmonic wave y = A sin[ k x t ] , where A = 1 meter, k has units of m 1 , has units of s 1 , and has units of radians, is plotted in the diagram below. +1 1 A (meters) x (meters) 10 20 30 At the time t = 0 Which wave function corresponds best to the diagram? 1. y = A sin bracketleftbiggparenleftbigg 2 3 m parenrightbigg x t parenleftbigg 2 3 parenrightbiggbracketrightbigg 2. y = A sin bracketleftbiggparenleftbigg 2 9 m parenrightbigg x t parenleftbigg 1 3 parenrightbiggbracketrightbigg 3. y = A sin bracketleftbiggparenleftbigg 2 3 m parenrightbigg x t parenleftbigg 5 3 parenrightbiggbracketrightbigg 4. y = A sin bracketleftbiggparenleftbigg 2 9 m parenrightbigg x t parenleftbigg 2 3 parenrightbiggbracketrightbigg 5. y = A sin bracketleftbiggparenleftbigg 2 3 m parenrightbigg x t parenleftbigg 1 3 parenrightbiggbracketrightbigg 6. y = A sin bracketleftbiggparenleftbigg 2 15 m parenrightbigg x t parenleftbigg 5 3 parenrightbiggbracketrightbigg 7. y = A sin bracketleftbiggparenleftbigg 2 9 m parenrightbigg x t parenleftbigg 4 3 parenrightbiggbracketrightbigg 8. y = A sin bracketleftbiggparenleftbigg 2 3 m parenrightbigg x t parenleftbigg 4 3 parenrightbiggbracketrightbigg 9. y = A sin bracketleftbiggparenleftbigg 2 9 m parenrightbigg x t parenleftbigg 5 3 parenrightbiggbracketrightbigg 10. y = A sin bracketleftbiggparenleftbigg 2 15 m parenrightbigg x t parenleftbigg 2 3 parenrightbiggbracketrightbigg correct Explanation: From the diagram of the wave function the wave-length = 15 m (6 horizontal scale di- visions of 2 . 5 m each, see diagram below). Notice: Since one wave-length is 2 ra- dians, each horizontal division is 2 6 = 3 radians. The given wave function (sine function with t = 0) y = A sin bracketleftbigg k x bracketrightbigg = A sin bracketleftbiggparenleftbigg 2 parenrightbigg x bracketrightbigg = A sin bracketleftbiggparenleftbigg 2 15 m parenrightbigg x bracketrightbigg (dark curve in diagram below) is shifted 2 divisions to the right (negative phase shift) of a no-phase-shift sine function y = sin bracketleftbiggparenleftbigg 2 15 m parenrightbigg x bracketrightbigg (gray curve in diagram below), therefore = 2 3 = 2 3 radians . Checking the wave function y at x = 0, we have agreement with the diagram below y = sin parenleftbigg 2 3 parenrightbigg = . 866025 m ....
View Full Document

{[ snackBarMessage ]}

### Page1 / 14

Exam 04 Solutions - midterm 04 GADHIA TEJAS Due May 2 2007...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online