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Unformatted text preview: myers (nmm698) HW07 Hamrick (54868) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A storm system is in the Central Texas area and moving in a straight line through Austin. The Weather Service Office forecasts that t hours after 12noon the the storm will be a distance of s ( t ) = 10 + 3 t- t 2 miles from Austin. How fast will the storm be moving at 3:00 pm and in what direction will it be moving? 1. storm speed = 5 mph, storm moving towards Austin. 2. storm speed = 3 mph, storm moving towards Austin. correct 3. storm speed = 3 mph, storm moving away from Austin. 4. storm speed =- 5 mph, storm moving towards Austin. 5. storm speed =- 3 mph, storm moving towards Austin. 6. storm speed = 5 mph, storm moving away from Austin. Explanation: Since s ( t ) =- ( t + 2)( t- 5) , the storm will pass through Austin at 5:00 pm. Now t hours after 12noon the velocity of the storm will be given by s ( t ) = 3- 2 t. Thus at 3:00 pm, t = 3 = s (3) =- 3 . To interpret the negative sign, observe that the storm will not have reached Austin at 3:00 pm, and hence will be moving towards Austin at that time. Consequently, at 3:00 pm the storm will be moving towards Austin with storm speed = 3 mph ....
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This note was uploaded on 03/10/2011 for the course M 408k taught by Professor Schultz during the Fall '08 term at University of Texas at Austin.
- Fall '08