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Ch 21, L4-AG, S'11

# Ch 21, L4-AG, S'11 - CHAPTER 21 Electric Field Field of a...

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CHAPTER 21 Electric Field

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Field of a ring of charge If x>> a, then this equation transforms to the Feld of a point charge ±ind electric Feld at a point P on the axis of the ring with radius a carrying a total charge Q at a distance x from its center Take into account symmetry of the ring to analyze Feld distribution: no vertical Feld component at any point on the ring axis " o = 8.85 # 10 \$ 12 C 2 /( N % m 2 ) E x = 1 4 "# 0 xQ ( x 2 + a 2 ) ! E = E x ˆ i = 1 4 0 xQ ( x 2 + a 2 ) ˆ i
The electric feld at the center oF this uniFormly charged ring 1. points up 2. points leFt 3. points right 4. points down 5. is zero + + + + + + + + + + + + + + + • P PRS Question

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Positive charge is uniformly distributed around a semicircle. The electric Feld that this charge produces at the center of curvature P is in A. the + x -direction. B. the – x -direction. C. the + y -direction. D. the –y- direction. E. none of the above PRS Question
Field of a uniformly charged disk If R>> x, then this equation transforms to: E = " 2 # 0 1 \$ 1 ( R 2 / x 2 ) + 1 % & ( ) * *

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Ch 21, L4-AG, S'11 - CHAPTER 21 Electric Field Field of a...

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