Moed_A_part_1_Solution

Moed_A_part_1_Solution - (236343) zeiaeyigd zxez...

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Unformatted text preview: (236343) zeiaeyigd zxez r"yz sxeg 1 wlg '` cren zepexzt 1 dl`y oky) ∅ ∈ S oky zil`ieeixh `l dpekz idef . S = L | L ∈ RE dpekz xicbp .qiix htyn it lr , L 1 / ∈ RE .1 ik d`xne o`k swz agxend qiix htyn ∅ ∈ S-y oeeikne ,( HP / ∈ RE oky) HP / ∈ S-e ( ∅ = Σ * ∈ R ⊆ RE . L 1 = L S / ∈ RE lry dpekn M x xy`k f ( h M i ,x ) = h M x i :jk xcbez divwecxd . HP ≤ L 2 divwecx zervn`a , L 2 / ∈ RE .2 dpere w lr M HP z` dvixn ,zxg` .dgec - dxvr M m`e ,micrv | w | jyna x lr M z` dvixn w hlw ,d`ln divwecx idef xexiaa .( HP ∈ RE oky efk zniiw) HP z` zlawn xy` dpekn M HP xy`k ,denk :divwecxd zetwz z` d`xp .dheyt divlitnew zlert zervn`a aeyigl zpzip `ide , L ( M x ) = HP miiwzi okle M HP enk dprz M x , w lkl okle x lr zxver dpi` M f` ( h M i ,x ) ∈ HP m` . h M x i ∈ L 2 lawp HP / ∈ RE-y oeeikne ekxe`y hlw lk dgcz M x okl .micrv k ixg` x lr zxver M-y jk irah k miiw f` ( h M i ,x ) / ∈ HP m` okle (milynl R zexibqn) L ( M x ) ∈ R ⊆ RE okle , L ( M x ) ∈ R okle ,ziteq...
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This note was uploaded on 03/12/2011 for the course CS 236343 taught by Professor Bensasson during the Winter '11 term at Technion.

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Moed_A_part_1_Solution - (236343) zeiaeyigd zxez...

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