# Exam 2.Answers - Exam II - October 17,2007 C hern 4 81 -...

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Exam II - October 17,2007 Chern 481 - Prof. T. Baer (Please print your name) Useful and essential information: R = 0.082 L-At/mK = 8.314 J/mK P = RT/(V-b) - aJV2 PV = RT[1 + (b - aIRT)V· 1 + (bN)2 ...] The following two lines refer to the properties of water in its various phases: il f HO[H 2 0(s)] = -291.8 kJI il f HO[H 2 0(f)] = -285.8 kJ/m il f HO[H 2 0(v)] = -241.8 kJ/m m P v298 = .032 atm c p [H 2 0(s)] = 38 J/m-K c p [H 2 0(1)] = 75 J/m-K cp[H 2 0(g)] = 33 J/m-K a.(H 2 0)=2.lxIO· 4 K'l Kr = 4.96xlO' s ar 1 il f HO[C0 2 ] = -393.5 kJ/m ilfHO[CO] = -110.5 kJ/m ilfHO[C~] = -74.8 kJ/m il f HO[C 6 H 6 ] = 49.0 kJ/m P = RT/(V-b) - aJV2 PV = RT[I + (b - alRT)V· 1 + (bN)2 ...] w=-PexdV w=-nRTlnV 2 N 1 ilU=q+w ilH=ilU+ilPV Cp-Cy=T(8P/OT)y(8V/8T)p=a.2TV/Kr a.=V· j (8V/8T)p Kr = _V· l (8V/8P)r ~ = [8T/8P]H = [T(8V/OT)p -V]c p · J 1tr = (8UJaV)r = T(8P/8T)y - P [T 2 /T 1 f vIR (8H/8P)r = -T(8V/OT)p + V = V\N 2 Chain Rule for XYZ: (8X18Y)z(8YJaZ)x(8Z18X)y =-1 H=U+PV A=U-TS G=H-TS dU=TdS-PdV

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## This note was uploaded on 03/14/2011 for the course CHEM 481 taught by Professor Berkowitz during the Spring '09 term at UNC.

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Exam 2.Answers - Exam II - October 17,2007 C hern 4 81 -...

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