{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Exam2.2009.solutions

Exam2.2009.solutions - Exam H — K 8 g Chem 481 — Prof T...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Exam H — October 21, 2009 K 8, g : Chem 481 — Prof. T. Baer {Please prin 'our name) Useful and essential information: _ R 2 0.082 L—At/mK 2 3.314 J/mK P = RT/(Vub) - 21sz PV = RT[1 + (b — a/RTN' 4 (W)2 ...] The following two lines refer to the properties of water in its various pheses: AfH°[H20(S)] = —291.8 kJ/ AfH°[H20(€)] = 985.8 kJ/m A;H°[H;O(v)} = -241.8 kJ/m P0293 = .032 atm CPU-120(3)] = 38 Jim-K _cp[H20(l)] =' 75 J/m—K CP[H20(g)] L 33 J/m—K a(H20):2. 14410414'E KT = 4.96x10'5 3:4 AfH°{cog] : -3935 kJ/m AfH°{c0] = -1 10.5 kJ/rn AfH°[CH4] = 44.3 kJ/m AfH°[C6H5] : 49.0 kJ/m P : RT/(V—b) — 2:sz PV = RT[1 + (b — a/RTW" + (b/V)2 ...] w = 43.de w = —nRTan2/V1 AU 74 q + w AH = AU + APv cP — cV = T(aP/6T)V(6V/6T)p = azTV/KT a=V" (6V/6T)p KT :— —v" (awaP)T p : [6T/6P}H = maven.) —V]cp" 7:4 = (aw/awT = Twp/am — P (6H/6P)T = -T(awa_r)P + v mm]CWR : WV2 Chain Rule for XYZ: (aX/av)z(aY/aZ)szex)Y = -1 H=U+PV AZU~TS G=H~TS dUszS—PdV (er/am = {cap/63).; (6T/6P)s = (EN/03)], (zap/am = (BS/8V)T (av/lamp = —(aS/6P)T (aG/EBP)T = v (an6131, = —s [0(AG/T) / (mp = AH/T2 {5(AG/T) / aamgp = AH dlnp/dT = AVH/RT2 as : [CV/T]dT + [aP/aTLdV d8 = [cp/Tm + [6V/6T]FdP dP/dT = AS/Av Show your work. N 0 credit without it. 1. (12 pts) Determine the expression for 7:? for a van der Waals gas, and calculate the AU when 1 mole of a van der Waals gas (IF -—0. 050L and a —— 24 atrnL2/moi2 ) lS isothermally expanded from V]— ._ l L to 20 L at 300K. .‘ 7.... .7. :90 e‘.—- 3 _T> _. T MR ”mg—t +£1.- (7-, L3“ tifi‘ v t V 10 V40 V2 at! a $7 .-—-v I v” f AU:S%1M (1(4264 “"T " . O ‘ - . 2. (24 pts) One .mole of an ideal gas [1 atm; 24.6 L; 300 K] is expanded isothermally to 10* by the following two paths: a) Reversible and b) against a constant pressure of 0.1 atm. Calculate the indICated quantities. Reversible Path: a) ’Rewmme, 9" WWS‘O“ _. - _ 22 w= 4550“ U0 2 "Kiev *-‘ "Say 3““?! a ct: +3505“:- AS = LééT/K e?) a €300 :- Against P=0.l atrn a...” 3. (10 pts.) What are the values of AG and AH when 1 mole of an ideal gas is isothermally compressed at 300 K from 1 to 10 atmospheres? 5 x ‘ LXI-lea :gn, smog. Peace/s4 3‘10th gag—V— a v drawer? 0156* ’ ”P . (28 pts) Consider the melting of ice at 0 and -10°C at 1 atm pressure. Calculate the indicated quantities for this phase transition. Use information for water and ice found on page 1. Assume that AmHmK = 6,000 I, and take into account that this changes with temperature. l0}— ac"? I AH _ LP[£\$)(‘Z€3"2-?3) was?) ~ 2&2 :3 Tcgpcgggétg i As a camaflm m ‘ 2 We» ,QA 'dl‘ __°jod ”Zéip’ €— 1, coco I __—-=? 1514,0C:@$3‘1 -toac, ice, me .02? ,l : €630? \ in: 0‘2; L55 610.9) W51 mmVUL$u\aQLg>a\i‘5L, Se; as) wan i: MMbwlclo «we Buzblfi/C W-e/Q 1 2‘ng + M fqg’ 23; L9 WEE-é 1?? 5. (10 pts) Starting with dH = TdS + VdP, derive an expression for (BHIBV)? in terms of RT, and V. VL— (JH IT 013 NW? :11 @310, 101 av uaééng‘rcm; 6. (16 pts) lmole of ice (Cp = 38 Jim—K) at 0 0C is dropped into 2 moles of liquid butanol (Cp = 60 Urn-K) at - 100 0C. What is the final temperature after the ice melts and reaches an equilibrium withthe butanol, and ' what is the entropy change of the butanol and the ice/water component? 0&9.ch— lel {—lv—s‘i‘ Wee/Vi. Milirwxitl wag“, A“) wdnufipujv A $000 I 1- CTSSWJCWO) : ($)(éoJ{z<)g:90«t) "@000 '1- 75'7“ I have neither given nor received aid on this exam . ' Please Sign ...
View Full Document

{[ snackBarMessage ]}