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Unformatted text preview: 1 reaches P r,min P r,min = 29log 10 (d min ) : d min = 10Pr,min/29 = 1083m d HO : received power at BS 1 reaches P r,HO P r,HO = 29log 10 (d HO ) : d HO = 10PrHO/29 So, 1083  10PrHO/29 > 4.5 Seconds 22.22 (m/s) S = 15dB, n = 4; N = ? I Distance travel during handoff = d min – d HO > 4.5 Seconds Mobile speed v P HO > 86.8 dBm Thus, Δ = P r,HO – P r,min Δ > 1.2 dB Q3.10 a) b) 90% or 100 Erlangs = 90 Erlangs 90 = UAu = U(0.1) : U = 900 Users c) Offered: 90E ; C = 100. So, 0.03 or 3% e) 24 MHz = 400 Channels 2.30 kHz 400 Channels = 100 Channels / Cells 4 Cells 2500 km 2 = 500 Cells : 500 x 900 Users/Cells = 450,000 users 5 km 2...
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This note was uploaded on 03/15/2011 for the course KICT CSC 4204 taught by Professor H during the Spring '11 term at International Islamic University Malaysia.
 Spring '11
 H

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