ProbSet3Solutions

# ProbSet3Solutions - Solution to Problem set 3 2.2 The...

This preview shows pages 1–5. Sign up to view the full content.

Solution to Problem set 3 2.2 The coulombic attraction is inversely proportional to the distance between the two oppositely charged ions so the ions with the shorter radii will give the greater coulombic attraction. The answer is therefore (c). 2.6 (a) 7 (b) 10 (c) 7 (d) 2 2.8 (a) [Kr]4d 10 5s 2 5p 6 (b) [Ar]3d 8 (c) [Xe]4f 14 5d 3 (d) [Kr] 2.14 (a) Au 3+ (b) Os 3+ (c ) I 3+ (d) As 3+ 2.20 (a) +2 (b) +2 due to inert pair effect, but 4+ is possible. (c) +3 (d) -1 (e) -2 2.24 (a) [Ar]3d 10 4s 2 ; no unpaired electrons (b) [Ar]3d 9 ; one unpaired electron (c ) [Xe]5d 10 6s 2 ; no unpaired electron (d) [Kr]; no unpaired electron 2.32 (a) FeS (b) CoCl 3 (c) Mg 3 P 2 2.34 (a) (b)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
(c) (d) 2.36 (a) (b) (c) (d) 2.40
2.46 (a) lower energy (b) As O O O O -1 -1 -1 -1 3- + As O O O O -1 -1 -1 3- 0 0 lower energy As O O O O 3- 0 0 0 0 3+ (c)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
O O O I O - 0 -1 0 +1 0 lower energy O O O I O - 0 -1 -1 0 O O O I O - 0 -1 -1 -1 O O O I O - -1 -1 -1 -1 +3 2.48 (a) The formal charge distribution is same for both structures. In the first, the end nitrogen atom is -1, the central N atom is +1 and O atom is 0. For the second
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 6

ProbSet3Solutions - Solution to Problem set 3 2.2 The...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online