ProbSet3Solutions - Solution to Problem set 3 2.2 The...

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Solution to Problem set 3 2.2 The coulombic attraction is inversely proportional to the distance between the two oppositely charged ions so the ions with the shorter radii will give the greater coulombic attraction. The answer is therefore (c). 2.6 (a) 7 (b) 10 (c) 7 (d) 2 2.8 (a) [Kr]4d 10 5s 2 5p 6 (b) [Ar]3d 8 (c) [Xe]4f 14 5d 3 (d) [Kr] 2.14 (a) Au 3+ (b) Os 3+ (c ) I 3+ (d) As 3+ 2.20 (a) +2 (b) +2 due to inert pair effect, but 4+ is possible. (c) +3 (d) -1 (e) -2 2.24 (a) [Ar]3d 10 4s 2 ; no unpaired electrons (b) [Ar]3d 9 ; one unpaired electron (c ) [Xe]5d 10 6s 2 ; no unpaired electron (d) [Kr]; no unpaired electron 2.32 (a) FeS (b) CoCl 3 (c) Mg 3 P 2 2.34 (a) (b)
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(c) (d) 2.36 (a) (b) (c) (d) 2.40
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2.46 (a) lower energy (b) As O O O O -1 -1 -1 -1 3- + As O O O O -1 -1 -1 3- 0 0 lower energy As O O O O 3- 0 0 0 0 3+ (c)
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O O O I O - 0 -1 0 +1 0 lower energy O O O I O - 0 -1 -1 0 O O O I O - 0 -1 -1 -1 O O O I O - -1 -1 -1 -1 +3 2.48 (a) The formal charge distribution is same for both structures. In the first, the end nitrogen atom is -1, the central N atom is +1 and O atom is 0. For the second
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ProbSet3Solutions - Solution to Problem set 3 2.2 The...

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