ProbSet4Solutions - Solutions to Problem Set 4 3.2 (a) The...

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Solutions to Problem Set 4 3.2 (a) The chlorate ion is trigonal pyramidal. (b) All the oxygen atoms are equivalent (resonance forms) so there should be only one O-Cl-O bond angle with a value close to 109.5 ° . 3.4 (a) The shape of XeF 5 + ion is square pyramidal based upon an octahedral arrangement of electrons about the Xe atom. (b) There are two types of F-Xe-F bond angles. (c) The Xe-F-Xe bond angles are approximately 90 ° and 180 ° . 3.10
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Ge H H H H (a) I 3 + should be bent with a bond angle of slightly less than 109.5 ° . AX 2 E 2 (b) PCl 3 is pyramidal with Cl-P-Cl bond angles of slightly less than 109.5 ° . AX 3 E. (c) SeO 3 2- is pyramidal with O-Se-O bond angles of slightly less than 109.5 ° . AX 3 E. (d) GeH 4 is tetrahedral with H-Ge-H angles of 109.5 ° . 3.12 P F F Cl Cl Cl Sn F F F F Sn F F F F F F 2-
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Xe O O O O a) PCl 3 F 2 is trigonal bipyramidal with angles of 120 ° , 90 ° , 180 ° . The most symmetrical structure is shown with all Cl atoms in equatorial positions. Phosphorus pentahalide compounds with more than one type of halogen atoms like this have several possible geometric arrangements of the halogen atoms. These different isomers are known as isomers. For this type of compound, the energy difference between the different isomers are low, so that the compounds exist as mixtures of different isomers that are rapidly interconverting.
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This note was uploaded on 03/15/2011 for the course CHEM 211 taught by Professor Crane, b during the Fall '06 term at Cornell University (Engineering School).

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ProbSet4Solutions - Solutions to Problem Set 4 3.2 (a) The...

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