Section3.2MarcKrishke - Marc Krishke Section 3.2 pp 190-191...

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Unformatted text preview: Marc Krishke Section 3.2 pp. 190-191 problems 1-45 odd 1. y = (x – 4) 2 – 3 The vertex is (4, –3) so the graph is B. 3. y = (x + 4) 2 – 3 The vertex is (–4, –3) so the graph is D. 5. P(x) = x 2 – 2x – 15 (a) P(x) = (x 2 – 2x + 1) – 1 – 15 = (x – 1) 2 – 16 (b) The vertex is (1, –16) (c) P(0) = 0 2 – 2(0) – 15 = –15 The y-intercept is (0, –15). Find the x-intercepts: x 2 – 2x – 15 = 0 x 2 – 5x + 3x – 15 = 0 x(x – 5) + 3(x – 5) = 0 (x – 5)(x + 3) = 0 x – 5 = 0 or x + 3 = 0 x = 5 or x = –3 The x-intercepts are (5, 0) and (–3, 0). Find few points: x-5-4-2-1 2 3 6 7 y 20 9-7-12-15-12 9 20 7. P(x) = –x 2 – 3x + 10 (a) P(x) = –x 2 – 3x + 10 = –(x 2 + 3x – 10) = 2 9 9 3 10 4 4 x x - + +-- 2 2 2 3 9 40 2 4 4 3 49 2 4 3 49 2 4 x x x = - +-- = - +- = - + + (b) the vertex is 3 49 , 2 4 - (c) P(0) = –0 2 – 3(0) + 10 = 10 The y-intercept is (0, 10) Find the x-intercepts: 2 2 3 10 5 2 10 ( 5) 2( 5) ( 5)(2 ) 5 2 5 2 x x x x x x x x x x x or x x or x-- + =-- + + =- + + + = +- = + =- = = - = The x-intercepts are (2, 0) and (-5, 0). Find few points: x-7-6-3 3 4 y-18-8 10-8-18 9. P(x) = x 2 – 6x (a) P(x) = x 2 – 6x = x 2 – 6x + 9 – 9 = (x – 3) 2 – 9 (b) The vertex is (3, –9) (c) P(0) = 0 2 – 6(0) = 0 The y-intercept is (0, 0). x 2 – 6x = 0 x(x – 6) = 0 x = 0 or x – 6 = 0 x = 0 or x = 6 The x-intercepts are (0, 0) and (6, 0). Find few points: x-2-1 1 5 7 8 y 16 7-5-5 7 16 11. P(x) = 2x 2 – 2x – 24 (a) P(x) = 2x 2 – 2x – 24 = 2(x 2 – x – 12) 2 2 2 2 2 1 1 1 1 2 12 2 12 4 4 2 4 1 1 48 1 49 2 2 2 4 4 2 4 1 49 2 2 2 x x x x x x =- +-- =--- =--- =...
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Section3.2MarcKrishke - Marc Krishke Section 3.2 pp 190-191...

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