2 Cable Problems - 3 sin 40 o mg T = The tension in the...

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Problem  6.1 kg store sign is hanging by a rope off a pole, the pole is attached to the wall of the store by a cable, the angle  between the cable and wall is 50 ° . If the sign remains hanging stationary in place, calculate the tension in the cable, you can  ignore the mass of the rod. Since the sign remains stationary then the sum of the moments about point A must equal zero 3 1 sin 40 0 o T l Tl - = where l is the length of the pole. 3 1 sin 40 0 o T T - = 1 3 sin 40 o T T = (1) Also the sum of all forces acting on the sign must equal zero ' 1 0 T mg + = uur ur ' 1 ' 1 ' 1 0 0 x F T mg T mg T mg = - = - = = By Newton’s third law ' 1 1 T T mg = = Substitute this in the eq. (1)
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Unformatted text preview: 3 sin 40 o mg T = The tension in the cable is 2 3 (6.1 )(9.8 / ) 93 sin 40 o kg m s T N = = Problem Consider a 100 N weight hanging from two cables attached to walls as shown. Calculate the tension/force in the second cable, T2. Since the weight remains stationary then the sum of all forces acting on the sign must equal zero 1 2 T T mg + + = uur uur ur 1 2 cos60 o x F T T =-= (1) 2 sin60 o y F T mg =-= (2) From the eq. (2) 2 2 2 sin60 sin60 sin60 o o o T mg T mg mg T-= = = 2 100 115 sin 60 o N T N = =...
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This note was uploaded on 03/16/2011 for the course PHYS 1 taught by Professor Landen during the Winter '11 term at Macomb Community College.

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