2C Exam 2 problems 10&amp;12

2C Exam 2 problems 10&12 - First note that the initial...

This preview shows page 1. Sign up to view the full content.

From Dr. Toupadakis's Chem 2C Miderm 2 Fall 2010 #10 is derived from the ideal gas law and is related to the reason we can use pressure and concentration interchangibily for activities and such. PV = nRT P RT = n V = mol L = M Therefore P is proportional to concentration with 1/RT as the proportionality constant. The units of Reaction Rate are M t so in terms of pressure, it must be P RT t or P RT t . #12 is an unfamiliar presentation of kinetic data that really tests the conceepts of chemical kinetics. I know Dr Toupadakis was particularly proud of this problem. It requires a really good understanding of the concepts, but the calculation itself is really simple.
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: First note that the initial rate follows the line drawn diagonally across the graph. The line is labeled as being at a 45 degree angle with the x-axis. That means the rise eqquals the run and the slope, [ A ] s , equals one, so the initial rate is 1 M/s. You are given k and from the units you should be able to tell it is a 2 nd order reaction. So the rate law is Rate = k [ B ] 2 . If you substitute in the information you know: 1 M s = 0.25 M − 1 s − 1 [ B ] 2 1 = 1 4 [ B ] 2 [ B ] 2 = 4 [ B ] 2 = 2 M...
View Full Document

This note was uploaded on 03/18/2011 for the course CHEM 2C taught by Professor Endrle during the Spring '08 term at UC Davis.

Ask a homework question - tutors are online