# Business Statistics Module 8 - A study has been carried out...

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A study has been carried out to compared the United Way contributions made by clerical workers A sample of clerical workers has been randomly selected from each firm, and the dollar amounts o are follows. (Use data file XR12027.) a. What are the null and alternative hypotheses for this test? H0: u1 = u2 = u3 H1: b. Use ANOVA and the 0.05 level of significance in testing the null hypothesis indentified in part (a Anova: Single Factor SUMMARY Groups Count Sum Average Variance Firm1 5 1119 223.8 1609.7 Firm2 6 889 148.17 3001.77 Firm3 6 951 158.5 1996.3 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 17845.81 2 8922.9 3.97 0.04 3.74 Within Groups 31429.13 14 2244.94 Total 49274.94 16 The F value is greater than the F critical value. P value is less than the level of significane. We will reject the HO and conclude that the average contributions may differ. u1 u2 u3

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from three local corporations. of their contributions Firm1 Firm2 Firm3 199 108 162 236 104 86 167 153 160 263 218 135 254 210 207 96 201 a).
For the following summary table for a one-way ANOVA, fill in the missing items (indicated by asterisks and alternative hypotheses, then use the 0.025 level of significance in reaching a conclusion regardin F Treatments 665 4 166.25 3.25 Error 3071.3 60 51.188 Total 3736.3 64 Variation Source Sum of Squares Degrees of Freedom Mean Square

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s), identify the null ng the null hypothesis.
From the one-day work absences during the past year, the personnel director for a large firm ha week for a random sample of 150 of the absences. Given the following observed frequencies, a conclude that one-day absences during the various days of the week are not equally likely? Monday Tuesday Wednesday Thursday Absences 42 18 24 27 Chi-Square Goodness-of-Fit Test Cell Frequencies: no. of paramet Observed (Oj): Expected (Ej): (Oj-Ej)^2/Ej: 42 30.00 4.800 18 30.00 4.800 24 30.00 1.200 27 30.00 0.300 39 30.00 2.700 P value is less than the level of significance. We will then reject the H0 and determine that the absences during anyday is not the same.

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as identified the day of the and fo rq = 0.01, can the director Friday 39 150 no. of cells, k = 5 ters estimated, m = 0 df = k - 1 - m = 4 culated chi-square = 13.800 p-value = 0.008
The outstanding balaces for 500 credit-card customers are listed in file XR13026. Using the 0.10 l whether the data could have come from a normal distribution. Balance 3917 Please see sheet 13.26: 3968 3176 P value is greater than the level of significance, therefore we will a 3318 determine that the population here could come from a normal dist 4282 3666 2585 3831 3684 4213 3857 3142 2876 3925 3131 3409 3288 3221 4050 3248 2743 3613 3094 3599 3215 2818 3417 3514 3330 3623 3769 3860 3897 3514 4121 3378 3846 3401 3186 2813 3268 3762

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3492 4095 4165 4252 3547 3483 3840 3691 3877 3584 3349 3541 4014 3475 2962 3618 2945 3917 2955 3119 3181 2921 4057 3379 3453 3736 3622 3338 3697 3771 3623 3512 3704 3696 3490 3722 3570 2987 3032 3813 3685 3361 3633 3472 3449
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3332 3497 2803 3975 2959 3318 4093 3673 3132 3516 3564 3765 3571 3848 3450 3264 4047 3503 3142 3614 3002 3110 3318 4087 3817 3719 3941 3701 3508 3262 3207 3319 4023 3451 3319 3403 3352 3416 3189 3246 3423 3742 3715 3692 3865
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3965 4083 3717 3048 3832 3476 3519 2870 3407 3422 3622 3281 3925 3456 3863 3776 3440 3615 3297 3452 3301 4036 3366 3827 3076 3458 3670 3388 3757 3103 4552 3804 3492 3682 3088 3099 4167 3864 3840 3569 3667 3158 3354 3351 3881
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3690 3157 3417 3193 3484 4389 3679 3500 3155 4167 4107 3556 3156 3821 3761 3804 3752
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## This note was uploaded on 03/18/2011 for the course BUS 360 taught by Professor Jamesgoff during the Spring '10 term at Grand Canyon.

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Business Statistics Module 8 - A study has been carried out...

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