Homework 03 Solutions

# Homework 03 Solutions - Gadhia Tejas – Homework 3 – Due...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Gadhia, Tejas – Homework 3 – Due: Sep 26 2007, 11:00 pm – Inst: James Holcombe 1 This print-out should have 27 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points The reaction A + B * ) C + 2D has an equilibrium constant of 3 . 7 × 10- 3 . Consider a reaction mixture with [A] = 2 . × 10- 2 M [B] = 1 . 7 × 10- 4 M [C] = 2 . 4 × 10- 6 M [D] = 3 . 5 × 10- 3 M Which of the following statements is defi- nitely true? 1. The system is at equilibrium. 2. No conclusions about the system can be made without additional information. 3. The reverse reaction can occur to a greater extent than the forward reaction until equilibrium is established. 4. Heat will be evolved. 5. The forward reaction can occur to a greater extent than the reverse reaction until equilibrium is established. correct Explanation: Q = [C][D] 2 [A][B] = (2 . 4 × 10- 6 M)(0 . 0035 M) 2 (0 . 02 M)(0 . 00017 M) = 8 . 64706 × 10- 6 Since Q < K the foward reaction is favored. 002 (part 1 of 1) 10 points Write the equilibrium constant for 2NaBr(aq) + Pb(ClO 4 ) 2 (aq) → PbBr 2 (s) + 2NaClO 4 (aq) . 1. K = 1 [Pb(ClO 4 ) 2 ][NaBr] 2 2. K = [PbBr 2 ] [Pb 2+ ][Br- ] 2 3. K = [NaClO 4 ] 2 [NaBr] 2 [Pb(ClO 4 ) 2 ] 4. K = [Pb 2+ ][Br- ] 2 5. K = 1 [Pb 2+ ][Br- ] 2 correct Explanation: 003 (part 1 of 1) 10 points An equilibrium in which processes occur con- tinuously, with NO NET change, is called 1. dynamic equilibrium. correct 2. hetergeneous equilibrium. 3. homogeneous equilibrium. 4. static equilibrium. Explanation: In dynamic equilibrium the forward and re- verse processes of the system continue but be- cause their rates are equal there is no change in the composition of the system. 004 (part 1 of 1) 10 points The expression for K c for the reaction at equi- librium is 4 NH 3 (g) + 5 O 2 (g) * ) 4 NO(g) + 6 H 2 O(g) 1. [NO] 4 [H 2 O ] 6 2. [NH 3 ] 4 [O 2 ] 5 3. [NO] 4 [H 2 O] 6 [NH 3 ] 4 [O 2 ] 5 correct 4. [NH 3 ] 4 [O 2 ] 5 [NO] 4 [H 2 O] 6 Explanation: The equation must be written with the ap- propriate formula and correctly balanced. K c is the equilibrium constant for species in so- lution and equals the mathematical product Gadhia, Tejas – Homework 3 – Due: Sep 26 2007, 11:00 pm – Inst: James Holcombe 2 of the concentrations of the chemical prod- ucts, divided by the mathematical product of the concentrations of the chemical reactants. In this mathematical expression, each concen- tration is raised to the power of its coefficient in the balanced equation. For K c the molar concentrations are used for the activities of the components. 005 (part 1 of 1) 10 points The equilibrium constant for the reaction 2SO 2 (g) + O 2 (g) * ) 2SO 3 (g) has the value K = 4 × 10 24 at 298 K. Find the value of K for the reaction SO 2 (g) + 1 2 O 2 (g) * ) SO 3 (g) at the same temperature....
View Full Document

{[ snackBarMessage ]}

### Page1 / 8

Homework 03 Solutions - Gadhia Tejas – Homework 3 – Due...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online