{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Sample Calculations for acid base reactions fall 2010-1

# Sample Calculations for acid base reactions fall 2010-1 - 1...

This preview shows pages 1–2. Sign up to view the full content.

1 Acid – Base Calculations Calculating KHP and NaOH E.g. 3.75 g of KHP was dissolved in a total of 50.0 mL with an indicator added. It takes 38.3 mL of the NaOH to reach the end point of the KHP solution. What is the molarity of the NaOH solution? What mass of KHP is necessary to react with 50.0 mL of 0.500 M NaOH? Calculating moles in a certain volume of a given molar concentration. circle5 E.g. How many moles of H 2 SO 4 are there in 48.5 mL of 0.275 M H 2 SO 4 solution? circle5 E.g. How many moles of H + ions are there in 48.5 mL of 0.275 M H 2 SO 4 solution? Calculating Solution Stoichiometry circle5 How many moles of NaOH will react with 48.5 mL of 0.275 M H 2 SO 4 solution? H 2 SO 4 (aq) + 2 NaOH 2 H 2 O (l) + Na 2 SO 4 (aq) ' ' ' ' L acid sol n mol acid moles acid L sol n L base sol n mol base moles base L sol n = = 2 4 2 4 2 4 2 4 0.0485 ' 0.275 0.0133 ' L H SO sol n mol H SO mol H SO L H SO sol n = 2 4 2 4 2 4 2 4 2 4 0.0485

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern