# Q2BSol - AM 250 Name Quiz#2 ID[Mitsslile 29th 2009 ®[11 1...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: AM 250 Name: Quiz #2 ID# [Mitsslile 29th, 2009 ® [11] 1. Solve the initial value problem: 3;” + 411’ + By = 48—3: + 1, y(0) = 2, y'(0) = 0. ‘1): ‘5“ i ‘36 Fm ‘31,.“ .mﬁttmsw (MV3)(P‘H)= 0 , ,se “Or" ~3Ae‘3i—g eurﬁm’ce 4%“ =9 ”6A 9:“ +‘fiA-t61’t + HA 'z‘t — 6:5“ “3(0‘11'1? g1: (‘Jrcﬂﬁlg :_ C‘i-Lzzgé \j‘ivFO #7 OT— -3C"L1"3' a M —;1£. ‘ u/s Cr- “V4 C1 7/; I41 2. In many applications a response can be used to determine properties of the system. To demonstrate the principle, consider the equation y" + :13," +133; = U, with the initial conditions y(0) = 1, y’([}) = 0, and determine the values of o: and {3 if the solution is found to be y = e"3* cos %t. -—-—7 «3+ cam +l3=0 m: -q 1 W you; it in, Salem, osdllmdc the I» we be a _ 2:7 ' ‘Eﬂc [C (.05 i wilt l (—3 9"" hrs-«113] 3} e ‘ "“1— We Fuel innue- ‘D-al—(T-‘ZL‘; 5° “:6. (9 M1 tip—«131) so “Wren“ 3 cl {2) l-‘r a 37 he 3 9‘ :2. a I} © . In class we discussed the mechanical oscillator with sinusoidal forcing: my” +cy’ +ky = F0 cos wt. We ﬁrst. reduced it to the standard oscillator DE: y” + 2wgCy’ + wgy 2 f0 cos wt, and then to fully non-dimensional form: Y" + 20” + Y = cos 97-. I’d like to see if you’ve understood what we’ve done. There are 9 constants here: m, c, 1:, F0, to, we, g, f0, and Q. Write the correct one beside its description below (please write clearly; if we can‘t tel] if you’re writing f9 or F0 we‘ll have to mark your answer wrong): L damping coefﬁcient (dimensionless) * \ In! ELM-l lnLOr‘Qck [9,"): . damping constant 5; {ﬁt A \ ‘mnw kg“ 9.. ram amplitude of reduced external force natural frequency ratio of forcing frequency to natural frequency spring constant ...
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern