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Unformatted text preview: Solution This problem is solved by using Equation 5.3 in the form J = ! D C A ! C B x A ! x B If we take C A to be the point at which the concentration of nitrogen is 4 kg/m3, then it becomes necessary to solve for x B, as x B = x A + D C A ! C B J 2200 # 5 % & 220d Assume x A is zero at the surface, in which case x B = 0 + ( 6 ! 1011 m2/s ) 4 kg /m3 2200 2 kg /m3 1.2 ! 10 2200 7 kg /m2  s # 5 % & 220d ( = 1 ⋅ 103 m = 1 mm...
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This note was uploaded on 03/21/2011 for the course CHE 332 taught by Professor Gregory during the Spring '11 term at Rhode Island.
 Spring '11
 Gregory
 pH

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