Unformatted text preview: M(0) +n(0)0+c =0 so C = 0 M(0)+n(2)(1)+C = 0 ……2n+1+0=0 so n = 1/2 M(3)+n(0)(4)+C = 0……3m+4=0 so m=4/3 Eq ===z=0+4/3*xy/2 Find Formula of linear function passing through (4,3,2) with slope 5 in x and 3 in y. Ax+By+CZ=0 put in points A(4)+3B+C+C = 0 Put in slopes: 4*5+3x3+2+C=0===C=13 Plane Eq = 5x3y13z=0 Linear = Z=5x3y13...
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 Spring '11
 Barabara
 Derivative, Slope, Trigraph, Linear function

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