243141 - Means each time u eat 2100 cals, you gain .0007...

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14.1 Fx (x,y) rate of change respect x = (f(x+h,y)-f(x,y))/h Fy(x,y) rate of change respect y = (f(x,y+h)-f(x,y))/h Eq of tan line: L(x) = f(a) +f’(a)(x-a) Fx = fix x……Fy = fix y F(x,y) = x^2+y^3 Find fx(2,1) fix y=1 and……f(x,1) = 2x=====4 Z = x^2y dz/dx = 2yx and dz/dy =x^2 Z=x^2e^(xy)……dz/dx = 2xe^(xy) + x^2ye^(xy) And dz/dy = x^2*xe^(xy)===x^3e^(xy) Suppose weight,w, function w = f(c,m) # cals, c, consume daily And num. mins, m, you exercise daily Units of dw/dc = lb/cal…meaning of dw/dc(2100,20)=0.007
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Unformatted text preview: Means each time u eat 2100 cals, you gain .0007 lb/cals Units of dw/dm=lb/min Dw/dm(2100,20)=-0.2=Exer above 20mins, 2100 fixed, lose 2/10s of a lb per min over 20 (neg=lose weight) W(2100,20)=120 . .dw/dm(2100,20)=-0.2. .Find w(2100,25) Well 5*(-.2)=1SO 120.1=119 lbs Table Prob. .>Estimate Fw(10,25)=dc/dw=2-10/15-10=-8/5f/mph Z=sin(xy^3). .dz/dx=cos(xy^3)*y^3----dz/dy=cos(xy^3)*3y^2x...
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