PHY3 - Howard (clh2528) homework #3 shubeita (57885) 1 This...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Howard (clh2528) homework #3 shubeita (57885) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Two slits are illuminated by a 551 nm light. The angle between the zeroth-order bright band at the center of the screen and the fourth-order bright band is 18 . 2 . If the screen is 155 cm from the double-slit, how far apart is this bright band from the central peak? Correct answer: 50 . 9614 cm. Explanation: Basic Concept: y = L tan . Solution: y = L tan = (155 cm) tan(18 . 2 ) = 50 . 9614 cm . 002 (part 2 of 2) 10.0 points What is the distance between the two slits? Correct answer: 0 . 00705653 mm. Explanation: Basic Concept: d sin = m Solution: The fourth-order bright band oc- curs when m = 4; therefore, d = m sin = 4 (551 nm) sin(18 . 2 ) = 0 . 00705653 mm . 003 10.0 points A light source emits visible light of two wave- lengths, 459 nm and 481 nm. The light im- pinges upon a double slit apparatus, schemat- ically shown below. y 6 1 . 54 m 25 . 3 m S 1 S 2 viewing screen Find the separation between the sixth- order bright fringes. Correct answer: 0 . 803478 cm. Explanation: Let : L = 1 . 54 m , d = 25 . 3 m , and m = 6 r 2 r 1 y L d S 1 S 2 = ta n 1 parenleftBig y L parenrightBig viewing screen d sin r 2- r 1 P O negationslash S 2 Q S 1 90 Q Using the equation y bright = m L d , with m = 6, we find that the values of the fringe positions corresponding to these two wavelengths are y (1) 3 = m 1 L d = (6) (4 . 59 10 7 m) (1 . 54 m) (2 . 53 10 5 m) = 0 . 167635 m , y (2) 3 = m 2 L d Howard (clh2528) homework #3 shubeita (57885) 2 = (6) (4 . 81 10 7 m) (1 . 54 m) (2 . 53 10 5 m) = 0 . 17567 m . Thus the separation between the two fringes is y = y (2) 3- y (1) 3 = (0 . 17567 m)- (0 . 167635 m) = 0 . 00803478 m = 0 . 803478 cm ....
View Full Document

Page1 / 5

PHY3 - Howard (clh2528) homework #3 shubeita (57885) 1 This...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online