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Unformatted text preview: Howard (clh2528) homework #3 shubeita (57885) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points Two slits are illuminated by a 551 nm light. The angle between the zerothorder bright band at the center of the screen and the fourthorder bright band is 18 . 2 . If the screen is 155 cm from the doubleslit, how far apart is this bright band from the central peak? Correct answer: 50 . 9614 cm. Explanation: Basic Concept: y = L tan . Solution: y = L tan = (155 cm) tan(18 . 2 ) = 50 . 9614 cm . 002 (part 2 of 2) 10.0 points What is the distance between the two slits? Correct answer: 0 . 00705653 mm. Explanation: Basic Concept: d sin = m Solution: The fourthorder bright band oc curs when m = 4; therefore, d = m sin = 4 (551 nm) sin(18 . 2 ) = 0 . 00705653 mm . 003 10.0 points A light source emits visible light of two wave lengths, 459 nm and 481 nm. The light im pinges upon a double slit apparatus, schemat ically shown below. y 6 1 . 54 m 25 . 3 m S 1 S 2 viewing screen Find the separation between the sixth order bright fringes. Correct answer: 0 . 803478 cm. Explanation: Let : L = 1 . 54 m , d = 25 . 3 m , and m = 6 r 2 r 1 y L d S 1 S 2 = ta n 1 parenleftBig y L parenrightBig viewing screen d sin r 2 r 1 P O negationslash S 2 Q S 1 90 Q Using the equation y bright = m L d , with m = 6, we find that the values of the fringe positions corresponding to these two wavelengths are y (1) 3 = m 1 L d = (6) (4 . 59 10 7 m) (1 . 54 m) (2 . 53 10 5 m) = 0 . 167635 m , y (2) 3 = m 2 L d Howard (clh2528) homework #3 shubeita (57885) 2 = (6) (4 . 81 10 7 m) (1 . 54 m) (2 . 53 10 5 m) = 0 . 17567 m . Thus the separation between the two fringes is y = y (2) 3 y (1) 3 = (0 . 17567 m) (0 . 167635 m) = 0 . 00803478 m = 0 . 803478 cm ....
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 Spring '08
 RITCHIE/LANG
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