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Blake 9-10-08

Blake 9-10-08 - 4 Multiply til Whole[Get the Empirical...

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Blake 9-10-08 Chemistry 1307 Acetylene, C 2 H 2 Benzene, C 6 H 6 Describe both in terms of % composition C 2 H 2 C 6 H 6 (C = 6 x 12.01 g/mol) = [72.06 g/mol] (H= 6 x 1.0079 g/mol) = [6.0474] 6.0474 + 72.06 = 78.11 g/mol TOTAL MASS OF BENZENE C = ([72.06/78.11] * 100 %) = 92.24 % H = ([6.0474/78.11] * 100 %) = 7.26 % % Composition to Formula (Combustion Analysis) A dipeptide that contains C, H, N, & O is used as a sweetener and is 32.7% C, 4.8% H, 19.0% N. What is the empirical formula of the dipeptide Poem 1. % to mass 2. Mass to mol (write formula) 3. Divide by small

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Unformatted text preview: 4. Multiply til Whole [Get the Empirical Formula] • C = (32.7/12.01 gfm) = 2.725 moles C • H = (4.8/1.0079 gfm) = 4.76 moles H • N = (19.0/14 gfm) = 1.357 moles N • O = (43.5/16 gfm) = 2.719 moles O • C 2.73 H 4.76 N 1.357 O 2.719 / 1.357 • C 2 H 3.5 NO 2 = C 4 H 7 N 2 O 4 Balancing Equations • Ammonia reacts with oxygen to form nitrogen monoxide and water. Write a balanced equation for this reaction. • C 1.33 (4/3) H 2.67 (8/3) N 1 (3/3) • 2NH 3 + 5/2O 2 = 2NO +3H 2 O [SAVE THE PURE ELEMENT FOR LAST]...
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Blake 9-10-08 - 4 Multiply til Whole[Get the Empirical...

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