Chapter 21 Solutions

Chapter 21 Solutions - wright (daw2557) Chapter 21 de...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: wright (daw2557) Chapter 21 de (14443) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Two identical positive charges exert a repul- sive force of 6 . 8 10 9 N when separated by a distance 3 . 7 10 10 m. Calculate the charge of each. The Coulomb constant is 8 . 98755 10 9 N m 2 / C 2 . Correct answer: 3 . 21837 10 19 C. Explanation: Let : F = 6 . 8 10 9 N , d = 3 . 7 10 10 m , and k e = 8 . 98755 10 9 N m 2 / C 2 . The electric force is F = k e q 1 q 2 d 2 d 2 F k e = q 2 q = radicalBigg d 2 F k e = radicalBigg (3 . 7 10 10 m) 2 (6 . 8 10 9 N) 8 . 98755 10 9 N m 2 / C 2 = 3 . 21837 10 19 C . 002 10.0 points A particle with charge- 6 C is located on the x-axis at the point 10 cm , and a second particle with charge- 6 C is placed on the x-axis at- 8 cm ....
View Full Document

This note was uploaded on 03/23/2011 for the course PHYS 1444 taught by Professor Sureshsharma during the Spring '09 term at UT Arlington.

Page1 / 2

Chapter 21 Solutions - wright (daw2557) Chapter 21 de...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online