Chapter 22 Solutions

Chapter 22 Solutions - wright(daw2557 Chapter 22 de(14443...

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wright (daw2557) – Chapter 22 – de – (14443) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0points An object having a net charge of 19 . 7 μ C is placed in a uniform electric field of 730 N / C directed vertically up. The acceleration of gravity is 9 . 8 m / s 2 . What is the mass of this object if it “floats” in the field? Correct answer: 1 . 46745 g. Explanation: Let : Q = 19 . 7 μ C = 1 . 97 × 10 - 5 C , E = 730 N / C , and g = 9 . 8 m / s 2 . Call the vertical direction the y -direction, so the the unit vector ˆ points up. Then force equilibrium in the vertical direction for a charge Q of mass m yields summationdisplay F = Q E ˆ + m g ( - ˆ ) = 0 For this to hold, Q E - m g = 0 m = Q E g = (1 . 97 × 10 - 5 C) (730 N / C) 9 . 8 m / s 2 × 1000 g 1 kg = 1 . 46745 g . 002 10.0points The electron gun in a television tube is used to accelerate electrons (mass of 9 . 10939 × 10 - 31 kg and charge of - 1 . 60218 × 10 - 19 C) from rest to 3 × 10 7 m / s within a distance of 6 . 3 cm.
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