Chapter 25 Solutions

# Chapter 25 Solutions - wright (daw2557) – Chapter 25 –...

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Unformatted text preview: wright (daw2557) – Chapter 25 – de – (14443) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points An air-filled parallel-plate capacitor is to have a capacitance of 0 . 7 F. The permittivity of free space is 8 . 85419 × 10- 12 C 2 / N · m 2 . If the distance between the plates is 1 . 3 mm, calculate the required surface area of each plate. Correct answer: 102 . 776 km 2 . Explanation: Let : C = 0 . 7 F , d = 1 . 3 mm = 0 . 0013 m , and ǫ = 8 . 85419 × 10- 12 C 2 / N · m 2 . The capacitance is C = ǫ A d A = C d ǫ = (0 . 7 F) (0 . 0013 m) 8 . 85419 × 10- 12 C 2 / N · m 2 × parenleftbigg 1 km 2 10 6 m 2 parenrightbigg = 102 . 776 km 2 . 002 10.0 points Consider the capacitor circuit E B 6 . 1 μ F 5 . 2 μ F 1 . 24 μ F 5 . 2 μ F 6 . 1 μ F 5 . 2 μ F 5 . 2 μ F a b c Find the equivalent capacitance between points a and c for the group of capacitors connected as shown.connected as shown....
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## This note was uploaded on 03/23/2011 for the course PHYS 1444 taught by Professor Sureshsharma during the Spring '09 term at UT Arlington.

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Chapter 25 Solutions - wright (daw2557) – Chapter 25 –...

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