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Unformatted text preview: 2 )/r or n + (mv 2 ) = mg Chapter 7: Dot product H = F d W tot = F net d W tot = K f K i W = .5k(x i 2 x f 2 ) Fs = kx Car moving at 5 m/s brought to stop. U = .2 what is the stopping distance? W f = k f k ium gd = .5m v 2 Chapter 8 Potential = mgy Elastic = .5kx 2 W nc = P + K Ei + Wnc = Ef m 1 g 1 h 1 = m 1 g 1 h f + .5m 1 v 2 m 2 g 2 h 2 = m 2 g 2 h f + .5m 1 v 2 Impulse = Force x time Impulse = v x t Bouncing: Init = 5 m/s Final = 3 m/s Change is 8 m/s NOT 2 Imp = P M1 is moving at a velocity of 5i 3j weighs 2 kg Momentum = 10i 6j M2 is moving at 7i 3j weighs 4 kg Momentum = 28i 12j Total K = 18i 18j Total weight = 6 So total v = 18/6i, 18/6j Inelastic collision m 1 v 1 + m 2 v 2 = (m 1 + m 2 )v f Elastic collision: P.E.  m 1 v 1 + m 2 v 2 = m 1 V 1f + m 2 v 2f K.E.  m 1 v 1 2 + m 2 v 2 2 = m 1 v 1f 2 + m 2 v 2f 2...
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This note was uploaded on 03/22/2011 for the course BME 111 taught by Professor Gokce during the Spring '11 term at NJIT.
 Spring '11
 Gokce

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