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Unformatted text preview: 2 )/r or n + (mv 2 ) = mg Chapter 7: Dot product H = F Â· d W tot = F net Â· d W tot = K f K i W = .5k(x i 2 â€“ x f 2 ) Fs = kx Car moving at 5 m/s brought to stop. U = .2 what is the stopping distance? W f = k f k ium gd = .5m v 2 Chapter 8 Potential = mgy Elastic = .5kx 2 W nc = P + K Ei + Wnc = Ef m 1 g 1 h 1 = m 1 g 1 h f + .5m 1 v 2 m 2 g 2 h 2 = m 2 g 2 h f + .5m 1 v 2 Impulse = Force x time Impulse = âˆ† v x t Bouncing: Init = 5 m/s Final = 3 m/s Change is 8 m/s NOT 2 Imp = P âˆ† M1 is moving at a velocity of 5i â€“ 3j â€“ weighs 2 kg Momentum = 10i â€“ 6j M2 is moving at 7i â€“ 3j weighs 4 kg Momentum = 28i â€“ 12j Total K = 18i â€“ 18j Total weight = 6 So total v = 18/6i, 18/6j Inelastic collision m 1 v 1 + m 2 v 2 = (m 1 + m 2 )v f Elastic collision: P.E.  m 1 v 1 + m 2 v 2 = m 1 V 1f + m 2 v 2f K.E.  Â½m 1 v 1 2 + Â½m 2 v 2 2 = Â½m 1 v 1f 2 + Â½m 2 v 2f 2...
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 Spring '11
 Gokce
 2 kg, 5k, 4 kg, 3 m/s

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