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EE 164 Problem Set 3 Solution

# EE 164 Problem Set 3 Solution - EE 164 Problem 1 Problem...

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EE 164 Problem Set 3 Spring 2005 Problem 1: A source emitting two wavelengths( 1 λ and 2 λ ) is intensity modulated at frequency m f . The power at 1 λ is ( ) 1 01 11 1 cos m P P P t ω φ = + + . The power at 2 λ is 2 02 22 P P P = + ( ) 2 cos m t ω φ + . Find an expression for the total power. Now assume that 1 m f kHz = . At the receiver 01 02 2 P P W µ = = , 11 22 1 P P W µ = = . Plot 1 P , 2 P , and total power (as a function of time) if 2 1 0 φ φ = . Repeat if 2 1 1.57 r φ φ = . Repeat if 2 1 3.14 r φ φ = . Plot the peak-to-peak value of AC power versus 2 1 φ φ . ( ) ( ) 1 2 01 02 11 1 22 2 cos cos T m m P P P P P P t P t ω φ ω φ = + = + + + + + ( ) ( ) 1 4 2cos 2 cos 2 T m P t ω φ φ φ = + + + ∆ where 2 1 φ φ φ = and we used the identity cos cos 2cos cos 2 2 A B A B A B + + = 2 1 0 φ φ = ( ) 1 4 2cos T m P t ω φ = + + ( ) 1 2 1 2 cos m P P t ω φ = = + + Problem 2: The power in a light beam is proportional to the square of the its electric field and

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EE 164 Problem Set 3 Solution - EE 164 Problem 1 Problem...

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