EE 164 Problem Set 3

EE 164 Problem Set 3 - EE 164 Problem 1 Problem Set 3...

This preview shows page 1. Sign up to view the full content.

EE 164 Problem Set 3 Spring 2005 Problem 1: A source emitting two wavelengths( 1 λ and 2 ) is intensity modulated at frequency m f . The power at 1 is ( ) 10 11 1 1 cos m PP P t ω φ =+ + . The power at 2 is ( ) 20 22 2 2 cos m PP P t + . Find an expression for the total power. Now assume that 1 m f = kHz. At the receiver 01 02 2 W µ == , 11 22 1 W . Plot 1 P , 2 P , and total power (as a function of time) if 21 0 −= . Repeat if 1.57 r = . Repeat if 3.14 r = . Plot the peak-to-peak value of AC power versus . Problem 2: As noted in Section 3.1, the power in a light beam is proportional to the squarre of the its electric field and the electric field for a beam traveling in an attenuating medioim can be given by Eq (3.8). The attenuation coefficient in that equation determines the loss. On the other hand, we more frequently discuss the loss in temrs of decibels per kilometer.
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/23/2011 for the course EEE 174 taught by Professor Kasab during the Spring '11 term at ASU.

Ask a homework question - tutors are online