Homework_Chapter_07

# Homework_Chapter_07 - EEE 165 CSUS Instructor Russ Tatro...

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Unformatted text preview: EEE 165 CSUS Instructor: Russ Tatro Chapter 7 Polarization and Modulation of Light S.O. Kasap, Optoelectronics and Photonics, Principles and Practices , 2001 Solutions to Chapter 7 Homework. Problems 8, 14, 15 8 L(quartz) = 16.2 µ m L(Calcite) = 0.86 µ m L(LiNbO 3 ) = 1.6 µ m 14 d/L = 0.6 x 10-3 15 Calculate V π only. V π = 15.5 V 7.8 Wave plates Calculate and compare the thickness of quarter -wave plates made from calcite, quartz and LiNbO 3 crystals all operating at a wavelength of λ ≈ 590 nm. What is your conclusion? Assuming little relative change in the indices, what are the thicknesses at double the wavelength? Solution Quarter-wavelength retardation is a phase difference of π /2 so that φ = 2 π λ n e − n o L = π 2 giving, L = 1 4 λ n e − n o Using n o and n e values from Table 7.1, p 281, in the textbook, Quartz L = 1 4 λ n e − n o = 1 4 (590 × 10 − 9 m) 1.5533 − 1.5442 = 16.2 µ m. Calcite L = 1 4 λ n e − n o = 1 4 (590 × 10 − 9 m) 1.486 − 1.658 = 0.86 µ m. LiNbO 3 L = 1 4 λ n e − n o = 1 4 (590 × 10 − 9 m) 2.29 − 2.20 = 1.6 µ m. At double the wavelength, simply double the above calculated thicknesses; and the thickness for calcite and LiNbO 3 become a little more manageable. 7.14 LiNiO 3 phase modulator: What should be the aspect ratio d/L for the transverse LiNiO 3 phase modulator in Figure 7Q14 that will operate at a free-space wavelength of...
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## This note was uploaded on 03/23/2011 for the course EEE 174 taught by Professor Kasab during the Spring '11 term at ASU.

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Homework_Chapter_07 - EEE 165 CSUS Instructor Russ Tatro...

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