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Unformatted text preview: Version One – Homework 3 – Savrasov – 39819 – Apr 24, 2006 1 This printout should have 5 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Accelerating an Electron 25:01, calculus, numeric, > 1 min, normal. 001 (part 1 of 1) 2 points Through what potential difference would an electron need to be accelerated for it to achieve a speed of 4 % of the speed of light (2 . 99792 × 10 8 m / s), starting from rest? Correct answer: 408 . 799 V. Explanation: Let : s = 4% = 0 . 04 , c = 2 . 99792 × 10 8 m / s , m e = 9 . 10939 × 10 31 kg , and q e = 1 . 60218 × 10 19 C . The speed of the electron is v = 0 . 04 c = 0 . 04 ( 2 . 99792 × 10 8 m / s ) = 1 . 19917 × 10 7 m / s , By conservation of energy 1 2 m e v 2 = ( q e )Δ V Δ V = m e v 2 2 q e = ( 9 . 10939 × 10 31 kg ) × ( 1 . 19917 × 10 7 m / s ) 2 2(1 . 60218 × 10 19 C) = 408 . 799 V . Falling Charged Particle 25:01, calculus, numeric, > 1 min, normal....
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 Spring '10
 Dr.AndyGavrin
 Potential Energy, Potential difference, Correct Answer

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