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Unformatted text preview: Version One – Homework 1 – Savrasov – 39821 – Apr 02, 2007 1 This printout should have 6 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Field in the Middle 23:07, trigonometry, numeric, > 1 min, nor mal. 001 (part 1 of 2) 1 points Two positive charges of 2 . 5 μ C each are 250 cm apart. Find the electric field midway between them. 1. E = 28760 . 2 N / C 2. E = 54950 . 8 N / C 3. E = 5321 . 43 N / C 4. E = 7181 . 54 N / C 5. E = 42376 . 7 N / C 6. E = 18335 N / C 7. E = 28898 . 3 N / C 8. E = 9751 . 04 N / C 9. E = 3335 . 02 N / C 10. E = 0 N/C correct Explanation: Let : q 1 = q 2 = 2 . 5 μ C = 2 . 5 × 10 6 C , x = 125 cm = 1 . 25 m , and k = 8 . 98755 × 10 9 N · m 2 / C 2 . The electric field due to a point charge a distance x away has a magnitude E given by E = k  q  x 2 . The electric field is zero because the electric field due to each charge is equal in magnitude and opposite in direction to that due to the other. 002 (part 2 of 2) 1 points What is the magnitude of the electric field if one charge is positive and the other negative, both of magnitude 2 . 5 μ C? 1. E = 28760 . 2 N / C correct 2. E = 45063 . 3 N / C 3. E = 9301 . 46 N / C 4. E = 40786 . 4 N / C 5. E = 4667 . 26 N / C 6. E = 55892 . 6 N / C 7. E = 5460 . 77 N / C 8. E = 80844 . 4 N / C 9. E = 79144 . 2 N / C 10. E = 0 N/C Explanation: Let : q 1 = 2 . 5 μ C , q 2 = 2 . 5 μ C , and x = 125 cm = 1 . 25 m ....
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This note was uploaded on 03/24/2011 for the course PHYS 13843 taught by Professor Dr.andygavrin during the Spring '10 term at IUPUI.
 Spring '10
 Dr.AndyGavrin

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