{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# xHW6 - Version One – Homework 6 – Savrasov – 39821...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Version One – Homework 6 – Savrasov – 39821 – May 14, 2007 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Lamps in Series 28:03, trigonometry, numeric, > 1 min, nor- mal. 001 (part 1 of 4) 1 points A 20 Ω lamp and a 5 Ω lamp are connected in series and placed across a potential of 50 V. What is the equivalent resistance of the circuit? Correct answer: 25 Ω. Explanation: Let : R 1 = 20 Ω , R 2 = 5 Ω , and V = 50 V . The equivalent resistance of the circuit is R = R 1 + R 2 = 20 Ω + 5 Ω = 25 Ω . 002 (part 2 of 4) 1 points What is the current in the circuit? Correct answer: 2 A. Explanation: I = V R = 50 V 25 Ω = 2 A . 003 (part 3 of 4) 1 points What is the voltage drop across the first lamp? Correct answer: 40 V. Explanation: This is a series circuit, so the voltage drop across the first lamp is V 1 = I R 1 = (2 A)(20 Ω) = 40 V . 004 (part 4 of 4) 1 points What is the power dissipated in the first lamp? Correct answer: 80 W. Explanation: P 1 = I V 1 = (2 A)(40 V) = 80 W . keywords: Three Parallel Resistors 28:04, trigonometry, numeric, > 1 min, nor- mal....
View Full Document

{[ snackBarMessage ]}

### Page1 / 4

xHW6 - Version One – Homework 6 – Savrasov – 39821...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online