1.1 Ch1-Calc-P20

# 1.1 Ch1-Calc-P20 - bandwidth each second IMPORTANT NOTES...

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Chapter 1 Powerpoint Slides, Page 20 How long does it take to send a file of 640,000 bits from host A to host B over a circuit-switched network? All links are 1.536 Mbps Each link uses TDM with 24 slots/sec 500 msec to establish end-to-end circuit 1.536 * 10 6 bit/sec ------------------------ = 64 * 10 3 bits/sec 24 slots/sec 640,000 bits -------------------- = 10 sec (i.e., 640,000 bits of data takes 10 slots) 64,000 bits/sec Total sending delay = 500 msec (to establish the end-to-end circuit) + 10 sec (to send data) = 10.5 seconds TDM frequency time 24 slots/sec Allocated 1/24 of the

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Unformatted text preview: bandwidth each second IMPORTANT NOTES (1) This calculation is only for the sending delay. The sending delay includes the set-up delay and transmission delay , but does not include the propagation delay or queueing/processing delays across the networks. (2) When considering transmission media and transmission rates, M (Mega) = 10 6 and K (Kilo) = 10 3 When considering data files for transmission, M (Mega) = 2 20 and K (Kilo) = 2 10 Question: If the problem had been stated as 640 Kbits of data. What would the sending time be?...
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## This note was uploaded on 03/24/2011 for the course CECS 572 taught by Professor Maples,t during the Spring '08 term at CSU Long Beach.

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1.1 Ch1-Calc-P20 - bandwidth each second IMPORTANT NOTES...

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