answer63 - 6301 a b =1 a2 b2 1 = c 2008 − c 2008 a 2009 b...

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Unformatted text preview: 6301 a +b =1 a2 b2 1 + = c 2008 − c 2008 a 2009 b 2009 + c 2008 ( 2008 − c ) 2008 ˆ µmè ‹ª ∵ a2 b2 1 ( a + b) 2 + = = c 2008 − c 2008 c + ( 2008 − c ) cb 20080 m cÈŒ µ a2 2008 − c b2c + = 2ab c 2008 − c 2 ∴∴ cb 20080 m cè‹ µ b a − = 0b c 2008 − c ab a b = 0 c 2008 − c c 2008 − c b bb 2008 2008 0 a b a+b 1 = = = b c 2008 − c c + ( 2008 − c ) 2008 a 2009 b 2009 + c 2008 ( 2008 − c ) 2008 1 20082008 µ m Œ Ȫ µ m Œ Ȫ * 2 2 2 b b c 2 + 2008 − c 2 ⋅ a + ≥ c ⋅ a + 2008 − c ⋅ c 2008 − c c 2008 − c a2 b2 + ) ≥ ( a + b) 2 c 2008 − c ∵ab b0 1 2008 ⋅ ( a2 b2 1 + ≥ c 2008 − c 2008 ´ ë •’F ™ Ð * ª ∴ a c= c b 2008 − c 2008 − c a b = c 2008 − c a b a+b 1 = = = c 2008 − c c + 2008 − c 2008 b ab c 2008 − c b bb 2008 2008 1 20082008 a 2009 b 2009 + c 2008 ( 2008 − c ) 2008 2^ ( 0 1. 8 " F › @ 7 0 2. o Ø p E@ › @ ` ;Ì ³´ 0 « … * ª á 5 6302 › @ F š 11 0 ƒ + h + / F š @ abcb b0c p ‘ 70 F › p + k ½ ¯ v à ° * ª ¶ ¥ p . 0 0Ø F¹ ™ Ð * ª } 0~999 0 , 9 3 + 9 2 + 9 = 819 93 5 × 9 2 = 405 1, 2, 3, … 8, 9, 1 12, …. x¶ , 1, ç* ª 2008 0 1000~1999 0 0 2000~2599 0 µª ˆm ( 0 819+ 9 3 +405+ 6 × 9 = 2007 0 2669 0 2008 0 26710 2007 0 0 ƒ½ ¾k _ ' @@› F E+ @p F ª µ m ˆ (* F 8+ ÿ ƒ½ ›c_k ™ Fð ¾ p™ ` F ª µ 13 (* mˆ 50 6303 11 × 12 × 13 × × 20 0 1 × 3 × 5 × × 19 11 × 12 × 13 × × 20 11 × 12 × 13 × × 20 × 2 × 4 × × 20 210 (1 × 2 × 3 × × 19 × 20) = = 1 × 3 × 5 × × 19 1 × 3 × 5 × × 19 × 2 × 4 × × 20 20! = 210 ⋅ 20 ! 10 = 2 = 1024 20 ! 18 Fπ ›ï™FàPh÷·ª* F ™ [email protected]*1Ì`&ºk+9 F ™ [email protected]*2Ì`&ºk+9 [email protected]_½k+p @ 50 6304 0 6 0 ë 4 hª* ´t $ºk+ á9 b 0 ` 24 `G ´ 24 hª* ët ´ 12 hª* ët 2` 3 10203í 04àª*ЙF ´G (1, 2)0(1, 2)0(1, 2)0(3, 4)0(3, 4)0(3,´ 4)h ªët 0 * ª´ë t h (1, 2)0(1, 2)0(3, 4)0(3, 4)0(1, 3)0(2,´ 4)¸Ð™F *ªíB (1, 2)0(1, 3)0(1, 4)0 (2, 3)0 (2, 4)0 (3, 4)0 × × × × × × × × × 8 F› š @ 0 3× 6! = 60 3 !× 3 ! @ × × × 0 × × × × × × × × × × × × × × × × × × × × × × × × 3× 2× 6! = 1080 2 !× 2 ! 6 ! = 720 60 +1080 + 720 = 18600 0 ª · ™F F ™ Ð*h÷·ª4Ì`&ºk+ @ ÷ h [email protected]_½k+p›F F › @ X @ 6305 CA b BD bI C B ∆AC * {ª ´ A CB > CA ∠ B C 60 D AB Èë B ∆AC î D • ∠ IDA 0 CB b I B A ª ¸m µ‰ CB C A1 b CA1 b CA b IA1 b IA b CI b BI b D ∵ CA1 b CA b ∠ 1 ∠ 2 CI b CI b ∴ ∆ ACI ≅ ∆ A1CI SAS AI b A1 I ʳ C 21 A1 B 3 4 I A ∵ BD b CB b CA b CB b CA1 b BA1 b ∠ 3 ∠ 4 BI b BI b ∆ A1BI ≅ ∆ DBIb SAS ∴ A1 I 0 DI AI b A1 I 0 DI b ‰ ¸m µ ª 0 ∆ ABC è´* ë{ª ∠ IDA ∠ IAD 1 ∠ DAC 300 2 D BC b CA b AB b E0 F0 G0 0 IE b IF b IG b ⇒AF b AG b BE b BG b CE b CF b ∵ CB b CA b BD ∴ GD b GB b BD b GB b CB b CA b EB b ( CE b EB ) CF b AF b AF b AG E I C F B D G A s IG b AB ë´ª* b 1. b $ºk+ á9 0 2. 5 14 F ë´ª* s 0 7 0 (11 0 )0 8 @@ 8 @ 7 @ 7 8 @ F $P 3 0 6 0 (1 0 )0 Å 0 5 0 (1 0 )0 Å 0 20 Å (1 0 )0 11 [email protected] A F f F Š F › ...
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This note was uploaded on 03/25/2011 for the course MATH 1232 taught by Professor Dr.jiangzhengchien during the Spring '11 term at Nanjing University.

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