Enzyme_Kinetics_Review

Enzyme_Kinetics_Review - Enzyme Kinetics 10-03-01 We want...

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Enzyme Kinetics 10-03-01 We want to study the simplest case, where an enzyme E binds a substrate S (sucrose) and an intermediate ES is produced. This intermediate then catalyzes the breakdown of the product into the two components, fructose and galactose. The reaction can be written in the absence of the enzyme as 2 1 2 S S O H S + + Where, S is sucrose (a disaccharide of fructose and galactose) S1 is fructose and S2 is galactose. The following picture shows how the reaction proceeds when the enzyme is present,
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This reaction can be summarized as follows 2 1 2 1 1 S S E kp O H ES k k S E + + + - + Where the k 1 and k -1 are the forward and backward reaction rates for the first reaction, and k p is the forward reaction rate for the last step We assume the following to be true 1) The first reaction is fast compared with the second, so that the first reaction is in equilibrium. 2) The backward reaction for the second reaction is small, so we can neglect it (k -p =0). Note that the first reaction is a binding reaction.
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This note was uploaded on 03/27/2011 for the course BIO 2912 taught by Professor Waring/rappaport during the Spring '11 term at Temple.

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Enzyme_Kinetics_Review - Enzyme Kinetics 10-03-01 We want...

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