This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: billing (cab4763) hw 3 opyrchal (121104) 1 This printout should have 14 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points An electric field of magnitude 2210 N / C is applied along the x axis. Calculate the electric flux through a rect angular plane 0 . 241 m wide and 0 . 84 m long if the plane is parallel to the yz plane. Correct answer: 447 . 392 N m 2 / C. Explanation: Let : E = 2210 N / C , = 0 , L = 0 . 84 m , and W = 0 . 241 m . The area of the rectangle is A = L W = (0 . 84 m) (0 . 241 m) = 0 . 20244 m 2 . Since the field is uniform,the flux is = E A = E A cos = (2210 N / C) (0 . 20244 m 2 ) (cos0 ) = 447 . 392 N m 2 / C . 002 (part 2 of 3) 10.0 points Calculate the electric flux through the same rectangle, if it is parallel to the xy plane. Correct answer: 0 N m 2 / C. Explanation: The angle is = 90 ,cos = 0 , and = E A = E A cos = (2210 N / C) (0 . 20244 m 2 ) (0) = 0 N m 2 / C . 003 (part 3 of 3) 10.0 points Calculate the electric flux through the same rectangle, but now the rectangle contains the y axis and its normal makes an angle of 63 with the x axis. Correct answer: 203 . 112 N m 2 / C. Explanation: Let = 63 = E A = E A cos = (2210 N / C) (0 . 20244 m 2 ) (cos63 ) = 203 . 112 N m 2 / C . 004 10.0 points A closed surface with dimensions a = b = . 578 m and c = 0 . 5202 m is located as in the figure. The electric field throughout the region is nonuniform and given by vector E = ( + x 2 ) where x is in meters, = 3 N / C, and = 3 N / (C m 2 ). E y x z a c b a What is the magnitude of the net charge enclosed by the surface? Correct answer: 7 . 73788 10 12 C. Explanation: Let : a = b = 0 . 578 m , c = 0 . 5202 m , = 3 N / C , and = 3 N / (C m 2 ) . The electric field throughout the region is directed along the xaxis and the direction of billing (cab4763) hw 3 opyrchal (121104) 2 d vector A is perpendicular to its surface. Therefore, vector E is parallel to d vector A over the four faces of the surface which are perpendicular to the yz plane, and vector E is perpendicular to d vector A over the two faces which are parallel to the yz plane. That is, only the left and right sides of the right rectangular parallel piped which...
View Full
Document
 Spring '10
 Fayngold
 Physics

Click to edit the document details