Unformatted text preview: Î” V > 0 and W = âˆ’ P âˆ« dV b) Calculate the final temperature of the gas. Show all work. T f = (P f V f )/(n f R) = (10 3 J/m 3 )(2.3 m 3 )/(1 mole * 8.314 J/(mole*K)) = 276.64 K c) Calculate the change in thermal energy Î” E th during the process. T i = (P i V i )/(n i R) = (10 3 J/m 3 )(1.3 m 3 )/(1 mole * 8.314 J/(mole*K)) = 156.36 K Î” E th = (3/2)*n*R* Î” T = 3*1 mole*8.314 J/(mole*K)*(276.64 K  156.36 K)/2 = 1500 J = 1.5 kJ d) What is the change in internal energy, Î” U, for the process? Explain. Î” U = Î” E th = 1.5 kJ, because Î” E bond = 0 e) Calculate the work in the process? ( Hint: you do not need to integrate the P(V) curve .) W = Î” U â€“ Q = 1500 J  2600 J = 1100 J...
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 Spring '08
 PARDINI
 Thermodynamics, Energy, Heat, ideal monatomic gas

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