7aCDW11quiz6

7aCDW11quiz6 - r 0 B) E bond = - ( ) N C) E bond = - (total...

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P7A Quiz6 DL Sec ___ Name ( last ) _______________________ ( first ) ____________________ I certify by my signature that I will abide by the code of academic conduct of the University of California. Signature ________________________________________ THERE IS A SECOND PROBLEM ON THE BACK Rubric Codes: 1. (12 pts) Look at the three configurations and determine which expression you should use to find the bond energy. Circle your choice and give a reason for your answer. There may be more than one correct answer for any configuration. r 0 A) E bond = ∑ (all pairs) PE pairwise B) E bond = - ± ( ²³´µ³¶·¸²³¹º»¼½µ¶ ´·½¾ ) N ε C) E bond = - (total number of nearest neighbor pairs) ε Reason for my choice: ___________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ A) E bond = ∑ (all pairs) PE pairwise
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Unformatted text preview: r 0 B) E bond = - ( ) N C) E bond = - (total number of nearest neighbor pairs) Reason for my choice: ___________________________________________________________________ _____________________________________________________________________________________ _____________________________________________________________________________________ A) E bond = (all pairs) PE pairwise B) E bond = - ( ) N C) E bond = - (total number of nearest neighbor pairs) Absolutonium has 6 nearest neighbors per atom Reason for my choice: ___________________________________________________________________ _____________________________________________________________________________________ 1 MOLE OF Absolutonium 2. (8 pts) Explain the difference between bond energy and binding energy. Your answer should include more than just an algebraic justification....
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7aCDW11quiz6 - r 0 B) E bond = - ( ) N C) E bond = - (total...

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