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Unformatted text preview: Positive, since V < 0 and W = P dV b) Calculate the final temperature of the gas. Show all work. T f = (P f V f )/(n f R) = (2*10 3 J/m 3 )(1.3 m 3 )/(1 mole * 8.314 J/(mole*K)) = 312.72 K c) Calculate the change in thermal energy E th during the process. T i = (P i V i )/(n i R) = (2*10 3 J/m 3 )(2.3 m 3 )/(1 mole * 8.314 J/(mole*K)) = 553.28 K E th = (3/2)*n*R* T = 3*1 mole*8.314 J/(mole*K)*(312.72 K - 553.28 K)/2 = -3000 J = -3 kJ d) What is the change in internal energy, U, for the process? Explain. U = E th = -3 kJ, because E bond = 0 e) What is the work in the process? ( Hint: you do not need to integrate the P(V) curve .) W = U Q = -3000 J + 7100 J = 4100 J...
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This note was uploaded on 03/27/2011 for the course PHY 7A taught by Professor Pardini during the Winter '08 term at UC Davis.
- Winter '08