Quiz 1 Key - 6 th order statistic is 49 and 7 th order...

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Quiz 1 Answer 1. 1) Sample mean : (30+10+4+37+24+60+49)/7=30.57 2) Sample median : 30. Rearranged data : { 4, 10, 24, 30, 37, 49, 60 } The sample size is 7 and 7 is an odd number. Thus the middle element 30 is the median. 3) Sample standard deviation: 20.082 4) 80 th percentile: 53.4 (1) Rearrange the sample data in increasing order {4, 10, 24, 30, 37, 49, 60} (2) Find p => p=.8 (3) (n+1)*p = 8*.8=6.4 Thus we want to find 6.4 th order statistic of the data set.
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Unformatted text preview: 6 th order statistic is 49 and 7 th order statistic is 60. The total distance is 11 units. We wish to go 40% of that, which is 4.4. The 80 th percentile is 53.4. 2. 1) Two events are independent. Therefore, P(A n B)=P(A)P(B). P(A U B)=P(A)+P(B)-P(A n B) = P(A)+P(B)-P(A)P(B)=1/5+1/4-1/20=8/20=2/5 2) Two events are mutually exclusive. Therefore, P(A n B)=0. P(A U B)=P(A)+P(B)-P(A n B) = P(A)+P(B)=1/5+1/4=9/20....
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This note was uploaded on 03/28/2011 for the course AMS 110 taught by Professor N/a during the Spring '08 term at SUNY Stony Brook.

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