Homeowrk 5 Solution

# Homeowrk 5 Solution - HW5 Solution 6.10 σ is not known and...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: HW5 Solution 6.10 σ is not known and n<30 => Definition 3 (a) 31.720 ; 8.729; 5 y mg s n = = = The standard error of the mean is 8.729 3.904 3.9 . 5 Y s SE mg n = = = ≈ (b) Sample size n=5 and the population standard deviation is not known. Therefore, we use Definition 3 in Lecture note 10&11. /2 /2 ( , ) s s x t x t n n α α- ⋅ + ⋅ The degree of freedom are n-1=5-1=4. We should find the 90% confidence interval, so α =.1 and /2 .05 2.776 t t α = = . The 90% confidence interval for μ is .05 .05 ( , ) 8.729 8.729 (31.720 2.776 , 31.720 2.776 ) 5 5 (23.4, 40.0) s s x t x t n n- ⋅ + ⋅ =- ⋅ + ⋅ = 6.12 σ is not known and n<30 => Definition 3 (a) 28.7; 4.5898; 4.5898 / 6 1.87 1.9 / . 28.7 (2.571)(1.9) (23.8,33,6) 23.8 33.6 / . y s SE g ml or g ml μ μ μ = = = = ≈ ± < < (b) μ = mean blood serum concentration of Gentamicin (1.5 hours after injection of 10mg/kg body weight) in healthy three-year-old female Suffolk sheep....
View Full Document

## This note was uploaded on 03/28/2011 for the course AMS 110 taught by Professor N/a during the Spring '08 term at SUNY Stony Brook.

### Page1 / 2

Homeowrk 5 Solution - HW5 Solution 6.10 σ is not known and...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online