2010 Bio 320 Question Bank E Key

2010 Bio 320 Question Bank E Key - BIO320 Answer key for...

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BIO320 Spring 2010 Answer key for question bank E I. Population genetics 1. C freq ( ii ) = 9% = 0.09 = q 2 , so q = 0.3 2. E freq ( aa ) = 0.49 = q 2 , so q = 0.7; p = 1-q = 0.3; freq ( AA ) = p 2 = 0.09 3.D q 2 = 1/1600; q = 1/40; p = 1-q = 39/40; freq (heterozygotes) = 2pq = 78/1600 4.D freq ( BB ) = p2 = 0.09; p = 0.3; q = 0.7; freq (heterozygotes) = 2pq = 0.42 = 42% 5.C freq ( g ) = 0.6 = q; freq ( G ) = p = 1-q = 0.4; freq ( GG ) = p2 = 0.16 6. E 7.A (genetic drift) 8. E. Freq (homozygous recessives) = q2 = 1/3600 so Freq (mutant allele) = q = 1/60 Freq (heterozygous carriers) = 2pq = 2 (59/60)(1/60). As 59/60 is almost = 1, this approximates to 2(1/60) = 1/30. The father is a known carrier, so the probability of a child being affected = prob (mother a carrier) x probability ( child is homozygous recessive) = ¼ x 1/30 = 1/120. 9 .D Freq ( b ) in mixed population = 0.8. The allele frequencies are not changed by mixing; they reach H-W equilibrium in 1 generation & will stay constant afterward, so freq ( bb ) in any generation = 0.8) 2 = 0.64 10.E freq ( Z ) in mixed population = 0.4, freq ( z ) = 0.6; freq (Zz) constant at 0.48 11.D Freq ( AA + Aa ) = 0.91, so freq ( aa ) = 0.09 = q2;
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2010 Bio 320 Question Bank E Key - BIO320 Answer key for...

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