{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Convolution_example - Graphically we can see that nothing...

Info iconThis preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
ECE476: Discrete Convolution Example Given: h={0.5, 2, 2.5, 1} x={1,1,1,0,0,0...} y n = k =−∞ x k ⋅ h n k = x n ∗ h n Let's graph the data as we would for a convolution (flipping 'h' along the y axis' and plot it for n=-1.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 6
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Graphically we can see that nothing overlaps. If we were to write out the equation for this. .. We can see that y[-1]=0. Now, let's step this along for n=0. If we continue along this line of thought...
View Full Document

{[ snackBarMessage ]}