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Assigned problems _5 answers

# Assigned problems _5 answers - Chemistry 2080 Spring 2011...

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Chemistry 2080 Spring 2011 Problem Set #5 - due date: Friday March 11th at 2 pm Name:________________ Lab TA Name:__________________ Lab Day/Time:______________________ 1) Hydrogen can be made from natural gas (methane) in a process known as “steam reforming”: CH 4 (g) + H 2 O(g) CO(g) + 3H 2 (g) The equilibrium constant K p for this reaction is 1.8 x 10 -7 at 600 K. Gaseous CH 4 , H 2 O and CO were introduced into an evacuated container at 600 K and their initial partial pressures (before reaction) were 1.40 atm, 2.30 atm, and 1.60 atm, respectively. Determine the partial pressure of H 2 (g) that will result at equilibrium. ___________________________________________________ First we will set up an ICE table: CH 4 (g) + H 2 O(g) CO(g) + 3H 2 (g) Initial (atm) 1.40 2.30 1.60 0.00 Change (atm) -y -y +y 3y Equilibrium (atm) (1.40-y) (2.30-y) (1.60+y) 3y So K p = [H 2 ] 3 [CO]/([CH 4 ][H 2 O]) = (3y) 3 (1.60+y)/((1.40-y)(2.30-y)) = 1.8 x10 -7 . . . . . . (1) Rather than solve the resulting quartic in y, since the value of K p is quite small, we will see if it is acceptable to make the simplifying assumption that y << 1.40 (and therefore that y<< 1.60 and y<<2.30). Making the assumption that y<<1.40 etc,

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