{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

10Abass - MATH 10A Bonus Assignment(Section B0 Name Due...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
MATH 10A Bonus Assignment Name (Section B0 ) Due February 9, 3:50pm in class. This assignment is worth up to 3 points on your Midterm 1 score. You may get help with these problems, but the solution should be written by you in your own words. Ex- plain your solution clearly. You are encouraged to use the midterm solutions as a guide. Problem 1: Find k so that the function f ( x ) = ( x + k, x 5 kx, 5 < x is continuous on any interval. Solution: Each piece of f is continuous. To make f continuous on any interval, we need in particular, to make the left and right hand limits agree at x = 5, and actually be equal to f (5). So we must solve 5 + k = f (5) = lim x 5 + f ( x ) = lim x 5 + kx = 5 k, which gives k = 5 4 . Problem 2: For the function f ( x ) = | 2 x - 6 | x - 3 , find lim x 3 + f ( x ) , lim x 3 - f ( x ) , and lim x 3 f ( x ) . Solution 1 (the graphical way): To obtain the graph of f ( x ), start with | x | x , translate it 3 units to the right, and stretch it vertically by a factor of 2 to get
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 2

10Abass - MATH 10A Bonus Assignment(Section B0 Name Due...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon bookmark
Ask a homework question - tutors are online