Homework11_70440836

Homework11_70440836 - 4.25 1 2 W=ABCD X=ABC ACD Y=AC D ABD...

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作业十一 4.25 1) 真值表略 2) 最简与或表达式如下: W = ABCD X = AB’C+ACD’ Y = AC’D+AB’D+A’BC+BCD’ Z = BD 3) 因为这是一个四输入和四输出的系统,所以一个 P16H8 PAL 可以满足需求。 4.30 七段显示形式对应的符号如下: 输入从高位到低位依次为 A,B,C,D ,那么可以得到最简形式如下(手动或者用编 程计算都可得到,最小公共乘积项的数目为 16 ): C0 = BC+A’B’C+AB’C’+AC’D+B’C’D+A’BC’D+AB’CD’ C1 = A’B’C’+A’B’C+ AB’C’+A’BC’D’+A’BCD+ABC’D+AB’CD’ C2 = A’B’C’+A’B+AB’C’+BC’D+B’CD+AB’CD’ C3 = A’B’C+B’C’D’+AC’D’+BC’D+B’CD+BCD’ C4 = AC+B’C’D’+AC’D’+A’CD’+ABC’D C5 = AC+AB’C’D+B’C’D’+AC’D’+BCD’+A’BC’D’+A’BC’D C6 = AC+AB’C’+A’B’C+BC’D+BCD’+A’BC’D’ 9.4 设定该状态机 9 个状态对应的编码分别为 0000 0001 00010 0011 0100
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Homework11_70440836 - 4.25 1 2 W=ABCD X=ABC ACD Y=AC D ABD...

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