solution1

solution1 - SEG4630Assignment#1Solution Q1.(3points)...

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Q1. (3 points) (1) (1 point) mean(A) = ∑(A) / n σ A  = (∑(A – mean(A)) / (n-1)   ) 0.5 Price Weight Mean 86.759 8.56 Q1 32.5 3.725 Median 58.485 4.85 Q3 126.375 6.575 Standard Deviation 81.57446962 10.55788057 Note: for Q1 (similarly for Q3), you can write any value between value d5  and d6, i.e., [31, 33] for price. So the answer for Q1 is not unique. An  alternative formula for standard deviation is  σ A  = (∑(A – mean(A)) / n) 0.5 . (2) (0.5 point) Min-Max Normalization Norm Price = (Price – 4.5) / (328 – 4.5) * (10 – 1) + 1 Norm Weight = (Weight – 1.4) / (38.2 – 1.4) * (10 – 1) + 1 Price  Weight  Norm Price  Norm Weight 5.89  1.40  1.038670788  1 149  1.50  5.020092736  1.024456522 59.98  2.20  2.543493045  1.195652174 129  2.70  4.463678516  1.317934783 15.89  3.20  1.316877898  1.440217391 56.99  3.90  2.460309119  1.611413043 35.75  4.10  1.869397218  1.660326087 42.19  4.10  2.048562597  1.660326087 31  4.60  1.737248841  1.782608696 125.5  4.80  4.366306028  1.831521739 4.5  4.90  1.855978261
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This note was uploaded on 03/29/2011 for the course SEEM 463 taught by Professor Hongcheng during the Spring '11 term at CUHK.

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solution1 - SEG4630Assignment#1Solution Q1.(3points)...

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