EX3.2 - CEE 415 Example 3.2: Calculate Mn and -factor for...

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CEE 415 Example 3.2: Calculate M n and φ -factor for the doubly reinforced section shown below. Assume that ε s y = 0.00207, and use trial and error process to find c : Try c d/3 5 in. c = 4 in. s ' = [( c - d )/ c ] cu = 0.0015 0.00113 f s ' = E s s ' = 43.3 ksi ( f y ) 32.6 ksi C s ' = A s ' ( f s ' – 0.85 f s ' ) = 72.2 k 52.6 k C c = 0.85 f c ' b β 1 c = 173 k 139 k T = A s f y = 190 k 190 k T < C c + C s ' (decrease c ) T C c + C s ' Check steel strain, s = [ (d – c)/c ] cu = 0.00863 > y (o.k.) Also, s > 0.005, so this is a tension-controlled member and
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This note was uploaded on 03/29/2011 for the course CEE 415 taught by Professor Wight during the Spring '11 term at University of Michigan.

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