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Unformatted text preview: With h CG = h/2 then F = h CG A = 62.4 h 2 6 h sin 60 o = 216.16 h 2. y cp = − 1 / 12 6 h sin 60 o 3 sin 60 o h 2 h sin 60 o = − h 6 1 sin 60 o . Taking sum of moments around B then ∑ M B = 10000 15 − 216.16 h 2 h 2sin 60 o − h 6sin 60 o − 3674 7.5cos60 o = which gives 83.2 h 3 = 136222.5 h = 1637.3 1 3 = 11.8 ft....
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- Spring '08
- Sakar
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