Gen 371 Final Exam 2010 - Gen 371 Final Exam 2010 1/26/11...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
1/26/11 4:20 PM Gen 371 Final Exam 2010 Page 1 of 9 http://courses.washington.edu/au371mkr/resources/problems/final_exam.html Final exam key 1. The efficiency of vitamin D synthesis is found to vary depending on the genotype at gene D as shown on the right. The pedigree below shows transmission of gene D and of a single nucleotide polymorphism (SNP). The SNP genotypes were detected by hybridization to allele-specific oligonucleotides as indicated below each individual. Shading indicates the base(s) detected at the SNP. (a) In the spaces provided above, fill in the genotypes of the parental type gametes that would be produced by II-1. (b) Consider the two scenarios outlined next and fill in the diagrams accordingly. Scenario A: II-1 and II-2 from the pedigree above have 4 children (III-1 to III-4). Despite the small sample size, the children show exactly the genotypes and proportions you would expect of independent assortment between the two loci. Write down genotypes for the vitamin D locus and shade the SNP hybridization diagrams to depict this scenario. For each child, use the box at the bottom to indicate if there is any evidence of having received a parental type gamete (P) or a non-parental type gamete (NP); leave blank if there is no evidence one way or the other. Home Course mechanics Help hours Calendar Syllabus Lectures, Podcasts Quiz Sections Practice problems Exams GoPost Send email to class Useful links The Gradiator
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
1/26/11 4:20 PM Gen 371 Final Exam 2010 Page 2 of 9 http://courses.washington.edu/au371mkr/resources/problems/final_exam.html The dad (II-2) is homozygous dd GG, so all the kids will receive dG from him. The mom is heterozygous with the parental types indicated in part (a). So, we expect to see: DC and dA (parental types), and DA and dC (non-parental) from the mom. Scenario B: II-1 and II-2 from the pedigree on the previous page have 6 children (III-1 to III-6). Only the last child (III-6) shows evidence of having received a recombinant gamete. Write down genotypes for the vitamin D locus and shade the SNP hybridization diagrams to illustrate this outcome. Here, III-1 through III-5 have to show parental types from mom -- so they each have to inherit DC or dA from mom (one example set of parental types is shown below; of course there are many other possible combinations). III-6 receives a non-parental gamete, which could either be DA or dC. (c) Based on Scenario B above, show the equation that you would set up for this family to calculate the LOD score for map distance = 12 cM between these two loci. (No need to calculate the final value, just set up the calculation.) (d) The parents in a different pedigree transmitting alleles of the same vitamin D gene are shown (along with parental type gametes that they would produce). Fill in the diagrams for their kids to illustrate two different examples of kids who would be informative for LOD score calculations and two different examples of kids who would be uninformative . For this particular pair of parents,
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 9

Gen 371 Final Exam 2010 - Gen 371 Final Exam 2010 1/26/11...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online