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Ohm&acirc;€™s law

# Ohm&acirc;€™s law - 0.79V When the current was 89...

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Akshay Patel Period 10 4/2/11 Honors Physics Lab- Ohm’s Law Objective: To determine the relationship between the voltage drop across and the current through an electrical component of unknown resistance. Conclusion: Ohm’s law states that the current through a conductor between two points is directly proportional to the potential difference or voltage across the two points. It is also inversely proportional to the resistance between them. The equation that describes the relationship between the current and the two points is V = IR. There are many relationships you can determine from calculating various currents. From working with these resistors and batteries in the experiment, you notice as you increase the current, the voltage drop increases. The lower the current is, the lower the voltage drop. This is also assuming you use the same resistor. When I measured 138 milliamps the voltage was 1.49V. Then, when I measured the current to be 72 milliamps the voltage was

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Unformatted text preview: 0.79V. When the current was 89 milliamps the voltage drop was 0.95V. The observed value for the resistor was calculated. We found it to be 11. The actual value for the resistor is 10 + 5 percent. We had the color code of brown-black-black-gold. This value was found through online. So we did observed-actual/actual. So 11-10.5 = 0.5. Then 0.5/10.5 times 100. You find the percent error to be 4.8%. Akshay Patel Period 10 4/2/11 There are many possibilities for sources of error. There is a possibility that we read the ammeter incorrectly. The instructor told us to read guess the ones place. The needle being in between the dashes was tough to read. Also there may have been some trouble with the batteries or the voltage meter. The readings may not always be precise. This is due to the battery being defective. The graph we plotted showed there is much error. We graphed the voltage vs. the current the relationship that we studied throughout this lab....
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Ohm&acirc;€™s law - 0.79V When the current was 89...

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